Again On simplification I get devaluate 3.11, multiplication 10 to the politics nuclei as the answer. So here I will use the formula and not difficult to are not by linda, which is equal to 115 x 3.7 033.70 to the multiplication 10 to the power minus five pulse. Finally I get the value of T Half 5.2 hour at the hub lifetime radioactive sample. To determine a half life, t, the time required for the initial concentration of a reactant to be reduced to one-half its initial value, we need to know: The order of the reaction or enough information to. Changing it in our I just multiplied by this value. For a second order reaction 2A products or A + B products (when A B), rate kA 2: t 1 / k A o Top. 693 by Linda, Linda is coming as 3.7 3.703 Multiplication tend to depart -5 pulse again on simplification I get the value of T. So I can calculate the value of the hub which is equal to. Now a decade constant is equal to 0.693 by T. Which is equal to 3.703 Multiplication 10 to the power minus five per second. I finally get the value of lame dad Long. Further solving I get the value uh -81 -8100 Linda is equal to long 0.741. I can write the expression, add just look at it carefully into the power minus lambda multiplication, 8100 2nd which is equal to 85.2 by 115 On. On simplification I can write 85 point to beat you is equal to 115 0.0 BQ multiplication E. Like in the value urgent, Just look at it carefully. Changing it in second, I just multiplied by 60 seconds per minute. Howard 15 minutes spending it in 2nd, I can write it as 1 20 minutes plus 15 minutes Which is equal to 1:35 minutes.

Half life in 60 seconds